nanotube input file - acell - explanation request
Posted: Sun Oct 10, 2010 12:01 am
Greetings,
I am beginning to work with Abinit, and yes I have seen the other posts by those already doing calculations on nanotubes (but hopefully I did not miss a pertinent one, or one that explains explicitly acell).
Suppose that I use the online TubeGen software to get the coordinates for a (2,2) tube (in bohrs)
1.402181 -0.000000 -1.233916
0.682146 1.225067 -1.233916
0.000000 1.402181 0.000000
-1.225067 0.682146 0.000000
-1.402181 0.000000 -1.233916
-0.682146 -1.225067 -1.233916
0.000000 -1.402181 0.000000
1.225067 -0.682146 0.000000
TubeGen's output also gives me the length = 4.66353(bohrs) and the diameter= 5.29948(bohrs). Now, if I visualize this (using Xcrysden) I see that the tube is aligned along the z-axis. Clearly if it is aligned along the z, looking at the z coordinates, my length is around 1.23Angstroms (2.32bohr). Visualizing with Xcrysden confirms TubeGens diameter of ~4.66bohrs. So I should use my directly visualized dimensions...
My guess, acell = 4.66353 4.66353 2.32
Is this acceptable for acell? I have negative coordinates for x,y, and not sure exactly how Abinit handles this. My understanding is that acell defines my unit cell. My end goal is that I want to calculate the band structure, do a GW calculation, etc, for a long tube. My logic tells me then if this unit cell is correct, then I can simply do for long tubes:
acell = 4.66353 4.66353 20*2.32 (for a tube 20*2.32 bohrs long)
I was reading a paper " Quasiparticle energies, excitonic effects and optical absorption spectra of small-diameter single-walled carbon nanotubes" and they talk about have an 'array' of tubes with an intertube distance of ~9.47angstroms. Am I incorrect in thinking about the acell above, in that it would simply be single tube replicated in the z-direction? I mention this paper because I have no idea why one would need to include tubes so far away...
thanks
I am beginning to work with Abinit, and yes I have seen the other posts by those already doing calculations on nanotubes (but hopefully I did not miss a pertinent one, or one that explains explicitly acell).
Suppose that I use the online TubeGen software to get the coordinates for a (2,2) tube (in bohrs)
1.402181 -0.000000 -1.233916
0.682146 1.225067 -1.233916
0.000000 1.402181 0.000000
-1.225067 0.682146 0.000000
-1.402181 0.000000 -1.233916
-0.682146 -1.225067 -1.233916
0.000000 -1.402181 0.000000
1.225067 -0.682146 0.000000
TubeGen's output also gives me the length = 4.66353(bohrs) and the diameter= 5.29948(bohrs). Now, if I visualize this (using Xcrysden) I see that the tube is aligned along the z-axis. Clearly if it is aligned along the z, looking at the z coordinates, my length is around 1.23Angstroms (2.32bohr). Visualizing with Xcrysden confirms TubeGens diameter of ~4.66bohrs. So I should use my directly visualized dimensions...
My guess, acell = 4.66353 4.66353 2.32
Is this acceptable for acell? I have negative coordinates for x,y, and not sure exactly how Abinit handles this. My understanding is that acell defines my unit cell. My end goal is that I want to calculate the band structure, do a GW calculation, etc, for a long tube. My logic tells me then if this unit cell is correct, then I can simply do for long tubes:
acell = 4.66353 4.66353 20*2.32 (for a tube 20*2.32 bohrs long)
I was reading a paper " Quasiparticle energies, excitonic effects and optical absorption spectra of small-diameter single-walled carbon nanotubes" and they talk about have an 'array' of tubes with an intertube distance of ~9.47angstroms. Am I incorrect in thinking about the acell above, in that it would simply be single tube replicated in the z-direction? I mention this paper because I have no idea why one would need to include tubes so far away...
thanks