- The array eigen1 contains the elements of the first order perturbing hamiltonian, as seen in Eq. (2) in doc/users/elphon_manual.pdf. If I write it to disk and then read into a complex array p(:,:,:), the first two indices are the final and initial bands (or vice versa, doesn't matter) and the third index is the k-point. This applies to a given direction and perturbation (q in <k+q|H'|k>) as specified by the input keywords.
- I find the phonon eigenvalues and eigenvectors (eivec 1 for anaddb) and perform the scalar products according to Eq. (2). Taking the |...|^2 of the result gives me the transition probabilities in atomic units (frequency in Ha/hbar). For the scalar product I assume both quantities are given in the same basis (real space?).
Is this basically correct?
What I don't entirely understand is the output regarding the phonon frequencies and eigendisplacements. In my case there are 6 phonon modes. This in indeed what I see in the output except that there are two eigendisplacements for each mode. For example:
Code: Select all
Mode number 1 Energy 0.000000E+00
Attention : low frequency mode.
(Could be unstable or acoustic mode)
- 1 0.00000000E+00 0.00000000E+00 1.45308842E-03
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
- 2 0.00000000E+00 0.00000000E+00 1.45308883E-03
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
Mode number 2 Energy 0.000000E+00
Attention : low frequency mode.
(Could be unstable or acoustic mode)
- 1 0.00000000E+00 1.45308842E-03 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
- 2 0.00000000E+00 1.45308883E-03 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
Mode number 3 Energy 0.000000E+00
Attention : low frequency mode.
(Could be unstable or acoustic mode)
- 1 1.45308853E-03 0.00000000E+00 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
- 2 1.45308872E-03 0.00000000E+00 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
Mode number 4 Energy 3.089754E-04
- 1 0.00000000E+00 0.00000000E+00 1.41990491E-03
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
- 2 0.00000000E+00 0.00000000E+00 -1.48704785E-03
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
Mode number 5 Energy 3.089754E-04
- 1 0.00000000E+00 1.41990491E-03 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
- 2 0.00000000E+00 -1.48704785E-03 0.00000000E+00
- 0.00000000E+00 0.00000000E+00 0.00000000E+00
Mode number 6 Energy 4.517583E-04
; 1 1.41990480E-03 0.00000000E+00 0.00000000E+00
; 0.00000000E+00 0.00000000E+00 0.00000000E+00
; 2 -1.48704796E-03 0.00000000E+00 0.00000000E+00
; 0.00000000E+00 0.00000000E+00 0.00000000E+00
I can see from the code that the numbers 1 and 2 refer to different atoms, but what does it mean? It gives me a total of 12 eigenvectors, which I'm not sure how to interpret. Also, apparently two modes have the same energy (degenerate) but are given the "-" symbol instead of ";". Is this correct? Finally, what does it mean that "The degenerate modes are not portable"?
Thanks