Dear ABINIT users:
Using the Optic to calculate semiconductor dielectric function, epsilon, it always showed small negative imaginary (epsilon2) value at the low imput energy between 0 to 1.0eV. It should be equal zero when the input energy approach to 0eV.
Is there any way to resolve this problem?
Regards
negative epsilon Im
Moderators: mverstra, joaocarloscabreu
Re: negative epsilon Im
Denny
I did found a similar problem, even by increasing the K points grid or the cutoff it remains and I did not find a way to go around. I did have to move to a
the dielectric calculation by using the GW approach. That gave me a much better agreement. Look at the GW tutorial and Matteo Giantomassi thesis,
there is a very nice description there!.
regards
-aldo
I did found a similar problem, even by increasing the K points grid or the cutoff it remains and I did not find a way to go around. I did have to move to a
the dielectric calculation by using the GW approach. That gave me a much better agreement. Look at the GW tutorial and Matteo Giantomassi thesis,
there is a very nice description there!.
regards
-aldo
Re: negative epsilon Im
Dear aromero,
Thanks for your comment! Could you give us the website that can download Matteo Giantomassi thesis?
Thanks for your comment! Could you give us the website that can download Matteo Giantomassi thesis?
Re: negative epsilon Im
Denny, if you send me a private message to my email, I can copy it to you, otherwise you need to check on the web. He did his PhD with Xavier Gonze
at UCL (Louvain Belgium)
let me know if I can help
regards
at UCL (Louvain Belgium)
let me know if I can help
regards
Re: negative epsilon Im
Matthieu Verstraete
University of Liege, Belgium
University of Liege, Belgium